Question

find k 2k+1,6k-7 and 8k+4 are in AP​

Answer 1

Answer:

as (2k+1) , (6k-7) , (8k+4) are in AP

then,

(6k-7)-(2k+1)=(8k+4)-(6k-7)

=> 6k-7-2k-1=8k+4-6k+7

=> 4k-8=2k+11

=> 4k-2k=11+8

=> 2k=19

=> k=19/2

=> k=9.5