Question

Find k and find a second solution
kx² -2x+k=0 one solution is -3

Answer 1

Answer:

Step-by-step explanation:given:kx$kx^{2} -2x+k=0$

if one solution is -3

put this in equation

we get: k{-3}^2-2{-3}+k=0

           9k+6+k=0

            10k+6=0

            10k=-6

           k= -6/10

          k= -3/2

to find another solution

put the value of k in equation

we get: -3/2x^2-2x-3/2=0

            take -  common and lcm of 2

3x^2+4x+3=0

x{3x+4}+3=0

as we know one solution of x

that is -3 put this in above eq

we get x +3/5