Question

find k for the equation kx( x -2) +6 =0 whose roots are equal​

Answer 1

Answer:

$k {x}^{2} - 2kx + 6 = 0 \:$

for equal roots, D =0

i.e b² – 4ac = 0

$( - 2k) {}^{2} - 4 \times k \times 6 = 0$

$4 {k}^{2} - 24k = 0$

$4k(k - 6) = 0$

$k = 0 \: \: \: or \: \: 6$

but k = 0 not satisfied eq hence

k = 6 Ans