Question

find k for which 2x²+kx+3=0, have equal roots
k=0
k=6
k=+2√6​

Answer 1

Answer:

answer is k=+2√6.

Step-by-step explanation:

using b²-4ac=0

(k)²-4(2×3)=0

k²-4×6=0

-24= -k²

24=k²

√24=k

2√6=k

Answer 2

Answer:

k=+2√6

Step-by-step explanation:

formula = b2-4ac

b=k

a=2

c=3

k2-4×(2×3)

k2-4×6

k2-24

k2=+24

k=+√24

k=+√2×2×6

k=+2√6