Find K for which equation has unique solution:
x - ky = 2; 3x + 2y + 5 = 0
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Answer:
The given system of equations are
x - ky – 2 = 0
3x + 2y + 5 = 0
This system of equations is of the form:
a1x+b1y+c1=0anda2x+b2y+c2=0
where,
a1=1,b1=-k,c1=-2anda2=3,b2=2,c2=5
Now, for the given system of equations to have a unique solution, we must have:
a1a2≠b1b2
⇒
13≠−k2
⇒
k≠-23
Hence,
k≠-23.
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