Find k' for which following equation has 4 solutions = |x - 1| - 2|x| + |2x + 1|= k
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8
Answer:
|x-1|-2|x|+|2x+1|=k
x+1-2x+2x+1=k
x+1+1=k
x+2=k
k=x+2
k-x=2
therefore now let k and x be a and b
therefore a-b =2
therefore we can write it as a-(a-b)=2
a-(a-b)=2
a-a+b=2
therefore a and a been cancelled therefore now
b=2
therefore a=a-a=0and b=2
therefore k=0and x=2
Answered by
0
Answer:
1<k<2 has 4 solutions
hope it useful
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