Question

find k for which
$2x {}^{2} + kx + 8 = 0$
have real root's ​

Answer 1

a=2,b=k,c=8

=b²-4ac

=(k)²-4*2*8

=k²-64

k=√8 answer

value of k is √8

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Answer 2

Heyaa☺

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Given,

b^2 - 4ac.

=》(k)^2 - 4(2)(8)

=》 k^2 - 64

=》 k = _/64

=》K = 8.

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Hope you understand..✌