find K for which the equation X square + 5kx + 16 is equal to zero has real and equal roots
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Let
x= 1, b= 5k c= 16
For equal roots,
b²-4ac=0
(5k)²-4.(1).(16)=0
25k²-64=0
k²=64/25
k = ± 8/5
jcxg:
how it became 8/5
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Answer:
Step-by-step explanation:
roots real and equal -----> delta >= 0.
----> 25 k^2 - 64 = 0 ----> k^2 = 64/25
-----> k = +- 8/5.
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