Math, asked by sanju3305, 10 months ago

Find K for which the given equation has unique solution 4x - 5y - k = 0 ; 2x - 3y -12 =0

Answers

Answered by mpreet196
1

Step-by-step explanation:

4x-5y-k = 0

2x-3y-12 = 0

a1 = 4, b1 = -5, c1 = -k

a2 = 2, b2 = -3, c2 = -12

a1/a2 ≠ b1/b2 ≠ c1/c2

4/2 ≠ -5/-3 ≠ -k/-12

2 ≠ 5/3 ≠ k/12

K ≠ 24 & K ≠ 20

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