Question

Find k for which the points (3k-1,k-2), (k,k-7), (k-1,-k-2) are collinear.

Answer 1

Step-by-step explanation:

3K-1 + K + K-1 = 180 ( THEY LIE IN X AXIS )

SUM OF ANGLES AT A POINT ON A STRAIGHT LINE

3K-2+ 2K =180

5K - 2 = 180

5K = 180 +2

5K = 182

K = 182 / 5

K = 36.4

36.4

HENCE K=36.4