Question

find k for which the sum and product of the roots of quadratic equation kx2 - 4x + 4k = 0 ae equal​

Answer 1

a =k, b=-4,c=4k
let the zeroes be x and y

sum of zeroes = -b/a
x+y = 4/k

product of zeroes = c/a
x*y= 4k/k

According to question
sum = product
x+y = x*y
$\frac{4}{k} = \frac{4k}{k} \\ 4k = 4 {k}^{2} \\ 4 = 4k \\ k = 1$

Answer 2

kx^2-4x+4k=0
two roots are
alpha and bita
ATQ/
alpha+bita=alpha× bita
-b/a=c/a
-(-4)/k=4k/k
4=4k
k=1