find k for which the system has no solution
Kx +2y- 5=0
3x +y- 1 =0
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Thus there is no solution for z = 0, so this is not a case of an infinite number of solutions. In conclusion with k = -29 there is no solution
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a1/a2=b1/b2#c1/c2. (# means not equal to)
k/3=2/1#(-5/-1)
k/3=2. and k/3#5
k=6. and k#15
Required value of k=6
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