Question

Find k for which the system kx-y=2 and 6x-2y=3 has a unique solution​

Answer 1

Step-by-step explanation:

6x−2y=3,kx−y=2

y=kx−2

6x−2(kx−2)=3

6x−2kx+4=3

x(6−2k)=−1

x=

6−2k

−1

k is not equal to 3 Since denominator