Question

find k given that k -1, 13, and 3k + 3 are consecutive terms of an arithmetic sequence

Answer 1

Answer:

2k+1,13 and 5k−3 are three consecutive terms of an A.P

Then, difference of first two terms is same as the difference of next two terms

∴ 13−(2k+1)=(5k−3)−13

⟹ 13−2k−1=5k−3−13

⟹ 12−2k=5k−16

⟹ 28=7k

∴ k=4