Question

Find K, given then the point (2, k) is equidistance from (3,7) and (9, 1)​

Answer 1

Step-by-step explanation:

The slope of the line segment joining (3,7) and (9,1) is -6/6 = -1.

Any point equidistant from those two points will lie on the perpendicular bisector of that line segment.

So, we want the line with slope=1, through (6,4), the midpoint of the segment.

y-4 = 1(x-6)

Now, we plug in (2,k) to get

k-4 = 2-6

k = 0

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Answer 2

Answer:

k = 0

Step-by-step explanation:

he slope of the line segment joining (3,7) and (9,1) is -6/6 = -1.

Any point equidistant from those two points will lie on the perpendicular bisector of that line segment.

So, we want the line with slope=1, through (6,4), the midpoint of the segment.

y-4 = 1(x-6)

Now, we plug in (2,k) to get

k-4 = 2-6

k = 0