Find k if (-2,2) is a solution of x+3y=k/2
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Answered by
1
substituting the values,
-2 + 3×2 = k/2
-2+6 = k/2
k/2 = 4
k = 4×2 = 8
-2 + 3×2 = k/2
-2+6 = k/2
k/2 = 4
k = 4×2 = 8
Answered by
0
You just have to substitute -2=x and 2=y
-2+3*2=k/2
-2+6=k/2
4=k/2
k=8
Hope this helps..!!
-2+3*2=k/2
-2+6=k/2
4=k/2
k=8
Hope this helps..!!
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