find K if 3is a solution of 3x ²+(k-3)x+9=0
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Given 3 is solution of the equation
Put x=3 in the equation
3*(3)^2+(k-3)3+9=0
27+3k-9+9=0
27+3k=0
3k=-27
k=-27/3
k=-9
Put x=3 in the equation
3*(3)^2+(k-3)3+9=0
27+3k-9+9=0
27+3k=0
3k=-27
k=-27/3
k=-9
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