Question

find k if 3k +2,4k+3 and 6k-1 are AP

Answer 1

value of k is 5
because
in a. p.
2b=a+c
2(4k+3)=3k+2+6k-1
8k+6=9k+1
k=5

Answer 2

the answer of the question is ,k=5
(3k+2)+(6k-1)=2(4k+3)
9k+1=8k+6
k=5