Find k if 3k+2,4k+3 and 6k-1 are in AP
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Given, 3k+2, 4k+3 and 6k+1 are in AP..
therefore, 2(4k+3)=(3k+2)+(6k+1)
. => 8k+6=9k+3
. =>. k=6-3
. => k=3.....
hence, required answer is 3
. hope it will help u..
therefore, 2(4k+3)=(3k+2)+(6k+1)
. => 8k+6=9k+3
. =>. k=6-3
. => k=3.....
hence, required answer is 3
. hope it will help u..
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