Question

Find K if 3x^2-k√3x+4=0 has equal roots.


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Answer 1

d=b^2-4ac
0=(-k√3)^2 - 4×3×4
0=3k^2-48
48=3k^2
48/3=k^2
16=k^2
k=4
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Answer 2

b= K root3
a=3
c=4
D = b^2-4ac=0
= 3k^2-4(3)(4)=0
=3k^2-48=0
=3k^2=48
k^2=48/3
k=root16
K = 4