Question

find K if 8, 15, k is an Pythagorean triplet

Answer 1

Given that 8, 15 and k are Pythagorean triplet.

It means that ---

${8}^{2} + {15}^{2} = {k}^{2}$

$Now, \: {8}^{2} = 8 \times 8 = 64 \\ \\ {15}^{2} = 15 \times 15 = 225 \\ \\ therefore \\ \\ 64 + 225 = {k}^{2} \\ \\ 289 = {k}^{2} \\ \\ or \\ \\ {k}^{2} = 289 \\ \\ k = \sqrt{289} \\ \\ k = \sqrt{ {17}^{2} } \\ \\ k = 17$

Therefore if 8,15 and k are Pythagorean triplets then k = 17

Answer 2

Answer:

k = 17

Step-by-step explanation:

Side 8, 15, k is a Pythagorean triplet,

k^2 = 8^2 + 15^2

k^2 = 64 + 225

k^2 = 289

k = √ 289

k = 17