Question

Find k if equation had equal roots:- Kx^2 + 4x + 1 = 0

Answer 1

Answer:

k=4

Step-by-step explanation:

k$x^{2}$+4x+1 has equal roots which means

$b^{2}$-4ac=0(where a=k;b=4;c=1)

$4^{2}$-4(k)(1)=0

16-4k=0

16=4k

k=$\frac{16}{4}$

k=4

Answer 2

k= 4

the roots of product is taken as AB and sum of roots as A+B