Question

find k if equation have equal roots (k+1) x²-2 (k+4) x-2k = 0​

Answer 1

Answer:

The value of k is 9.477 if equation have equal roots.

Step-by-step explanation:

As per the data given in the question,

We have to calculate the value of K.

As per questions

It is given that

(k+1) x²-2 (k+4) x-2k = 0​

Here a=(k+1) , b= (-2(k+4)) and c=-2k

As we know equation have equal roots i.e D=0

⇒$b^{2}-4ac =0$   (The value of D=$b^{2}-\sqrt{4ca}$ )

$(-2 (k+4))^{2}$-4×(-2k)×(k+1)=0

⇒$k^{2}+8k+16-2k^{2}-2$=0

⇒-$k^{2}+8k+14$ =0

⇒$k^{2}-8k-14=0$

Perform any multiplication or division, from left to right

so, the value of k=$\frac{8+-\sqrt{120} }{2}$

then calculate K1 = $\frac{8+\sqrt{120} }{2}$=9.477

Again calculate K2 = $\frac{8-\sqrt{120} }{2}$ = -1.477 (negative answer is not taken )

Positive value should be the answer.

Hence, the value of k is 9.477 if equation have equal roots.

For such type of questions :

https://brainly.in/question/23274117

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