Question

.Find K if equation kx² + 4x + 1= o If the equation has real and equal roots. *

Answer 1

Step-by-step explanation:

..... THALAPATHY FAN....

Answer 2

✓ Given :

$\longrightarrow {kx}^{2}+4x+1=0 \\ \: \: \: has \: real \: and \: equal \: roots \:$

✓ To find :

» The value of k

✓ Solution :

$p(x) = {ax}^{2} + bx + c = 0$

here a = k , b = 4 and c = 1

Here they had given that The roots are real and equal.

» D = 0

$d = {b}^{2} - 4ac$

${b}^{2} - 4ac = 0 \: \: \: { here}$

$d = {4}^{2} - 4(k)(1) = 0$

$= 16 - 4k = 0$

$4k = 16$

$\therefore \: k \: = 4$

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