Find k if f(x)=k sin 90(x+1);x=0
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Answered by
0
k=0
As
0=k×1×(0+1)
0=k×1×1
0=k
Hence k=0
As
0=k×1×(0+1)
0=k×1×1
0=k
Hence k=0
Answered by
0
sin 90
K sin 90(x+1)=0
k *1*(0+1)=0
k*1=0
k=0
K sin 90(x+1)=0
k *1*(0+1)=0
k*1=0
k=0
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