Question

Find k if k+1, 2k+2 ,3k+4 are in AP​

Answer 1

Answer:

i am sooo small for this question.....

Answer 2

Answer:

2(2k+2) = k+1+3k+4

4k+4 = 4k+5

it's common difference is changing first k+1 and then k+2

so this AP does not exist