find k if (k+1)X+y=1 and 3x+(k-1)y=2k+5 has no solution
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3x + y =1
(2k-1)x+(k-1)y=2k+1
=> 3x+y-1=0
(2k-1)x+(k-1)y-2k-1 =0
We know,
a1/a2 = b1/b2 not equal to c1/c2 has no solution
Now,we have,
a1=3 , b1=1
a2=2k-1 , b2 = k-1
3/2k-1 = 1/k-1
3(k-1) = 2k -1
3k-3 = 2k -1
3k -2k = -1 +3
k = 2
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