Question

Find k if (k-12) x² + 2(k-12 + 2 = 0

has real and equal roots​

Answer 1

Answer:

k = 14

Step-by-step explanation:

a = k-12 b = 2 ( k - 12 ) c = 2

D = b² - 4 ac

[ 2 ( k - 12 ) ]² - 4 ( k - 12 ) ( 2 )

4 ( k - 12 )² - 8 [ k - 12 ]

Roots are equal if D = 0

4 ( k - 12 )² - 8 ( k - 12 ) = 0

4 ( k - 12 ) ( k - 12 - 2 ) = 0

( k - 12 ) ( k - 12 ) = 0

k = 12 or k = 14

But k = 12 does not satisfy the equation

k = 14