Question

find k if m=-7/5is a root of equations 5m2+2m+k=0​

Answer 1

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find k if m=-7/5is a root of equations 5m2+2m+k=0

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$= > 5 {m}^{2} + 2m + k = 0$

=>put the value of m=-7/5 in the Equation :

$= > 5 \times( { - \frac{7}{5}) }^{2} + 2 \times - \frac{7}{5} + k = 0$

$= > 5 \times \frac{49}{25} - \frac{14}{5} + k = 0$

$= > \frac{49}{5} - \frac{14}{5} + k = 0$

$= > \frac{35}{5} + k = 0$

$= > 7 + k = 0$....(I)

$\bold{\red{= > k = - 7}}$

check from Equation1

=>7+k=0

=>7-7=0

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Answer 2

Answer:

-7

Step-by-step explanation:

-7/5 is root of eqn  $5m^{2}$+2m+K=0 so it satisfies it

$5(-7/5)^{2}$+2(-7/5)+k=0

5×(49/25)-14/5+K=0

49/5-14/5+K=0

35/5+K=0

K= -7