Find k if matrix x 22 [ 7 -2 3 k ] is singular.
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Answer:
Given, A=[2−k123−k]
Also given A is singular.
⇒∣A∣=0
Thus ∣∣∣∣∣∣2−k123−k∣∣∣∣∣∣=0(2−k)(3−k)−2=0
⇒6−2k−3k+k2−2=0⇒k2−5k+4=0⇒k2−5k=−4⇒5k−k2=4
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