Question

find k if
one root
of quadratic equatim 2x2 + kx-2=0
is
-2​

Answer 1

Answer:

The value of k is 1

Step-by-step explanation:

Given: $2x^{2} +kx -2=0$ ---------------------(1)

and one root= x = -2

Proof: Put x = -2 in equation (1)

$2(-2)^{2} + k(-2) - 2 =0\\=>2(2) - 2k - 2 = 0\\=>4 -2k - 2=0\\=>2(2-k-1) = 0\\=>2-k-1 = 0\\=>k = 1$

Therefore,the value of k = 1

Hence proved

Thanks!