Find k if one zero kx²-x+1/3 is reciprocal of other
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Given a quadratic equation:2x² – 3x + k
Also given one of the zeros of 2x² – 3x + k is reciprocal to the other,
We need to find the value of k.
Solution
Let us assume that one zeros of the given quadratic equationbe(2x² – 3x + k) be α
Hence the other zero is reciprocal of the zero. So the other zero is 1/α
As per the given equation
a = 2 b = -3 c = k
So, α x 1/α = c/a
1 = k/2
k = 2
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