find k if one zero of the quadratic polynomial X²- 2x + 3 is 2.
Answers
Answered by
4
Heya !!!
It seems your question is wrong.
Right question :- X² - 2K + 3
Or (K)² - 2X + 3 OR X² - 2X + 3K
P(X) = X² - 2K +3
P(2) = (2)² - 2K + 3
=> 4 - 2K +3 = 0
=> -2K = -7
=> K = 7/2
Or,
P(X) = K² - 2X + 3
P(2) = K² - 2 × 2 + 3
=> K² - 4 + 3 = 0
=> K² = 7
=> K = ✓7
Or,
P(X) = X² -2X + 3K
P(2) = (2)² - 2 × 2 + 3K
=> 4 - 4 + 3K = 0
=> 3K = 0
=> K = 0/3 = 0
★ HOPE IT WILL HELP YOU ★
It seems your question is wrong.
Right question :- X² - 2K + 3
Or (K)² - 2X + 3 OR X² - 2X + 3K
P(X) = X² - 2K +3
P(2) = (2)² - 2K + 3
=> 4 - 2K +3 = 0
=> -2K = -7
=> K = 7/2
Or,
P(X) = K² - 2X + 3
P(2) = K² - 2 × 2 + 3
=> K² - 4 + 3 = 0
=> K² = 7
=> K = ✓7
Or,
P(X) = X² -2X + 3K
P(2) = (2)² - 2 × 2 + 3K
=> 4 - 4 + 3K = 0
=> 3K = 0
=> K = 0/3 = 0
★ HOPE IT WILL HELP YOU ★
surya828:
actually i posted wrong question
Answered by
3
Your question needs a correction :
Correct equation : x² - 2kx + 3
=> x² - 2kx + 3 = 0
=> (2)² - 2(2)k + 3 = 0
=> 4 - 4k + 3 = 0
=> 7 - 4k
=> 7 = 4k
=> 7/4 = k
Correct equation : x² - 2kx + 3
=> x² - 2kx + 3 = 0
=> (2)² - 2(2)k + 3 = 0
=> 4 - 4k + 3 = 0
=> 7 - 4k
=> 7 = 4k
=> 7/4 = k
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