Find k if quadratic equation x^2 + kx + k = 0 has positive roots.
Answers
Answered by
7
it should be equal roots
so discriminamt =0
k.k- 4k = 0
k(k-4) = 0
k = 0,4
so discriminamt =0
k.k- 4k = 0
k(k-4) = 0
k = 0,4
Answered by
12
Solution:
For positive root,
Discriminate Must be > 0
Thus, D = b² - 4ac
Here, b = k , a = 1 & c = k
=> D = k² - 4×1×k > 0
=> k(k-4) > 0
=> k > 4 or k > 0
Thus, value of k is Natural number.
_______________
Amrit⭐
For positive root,
Discriminate Must be > 0
Thus, D = b² - 4ac
Here, b = k , a = 1 & c = k
=> D = k² - 4×1×k > 0
=> k(k-4) > 0
=> k > 4 or k > 0
Thus, value of k is Natural number.
_______________
Amrit⭐
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