find K if roots of (K + 2 ) x square - 8 x + 2 k + 3 = 0 are reciprocal of each other
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if the roots are reciprocal of each other
then,
one root is ß and other is 1/ß
product of roots=1/ß*ß
product of roots=1
but,
product of roots=c/a
therefore,
c/a=1
2k+3/k+2=1
2k+3=k+2
2k-k=2-3
k=-1
hope it helps
:-)
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