Find k if roots of x2+ 5x+k=0 are real and
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Answer:
kx
2
−5x+k=0
Here a=k,b=−5,c=k
Given that the equation has equa roots.
Therefore,
D=0
b
2
−4ac=0
(−5)−4(k)(k)=0
25−4k
2
=0
⇒4k
2
=25
⇒k=±
4
25
=±
2
5
Hence the value of k is ±
2
5
.
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