Find k,if the area of the triangle whose vertices are (1,-1),(-4,2k),(-k,-5) is 24 sq.units
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ar triangle =24 x 2
=> [ 1 ( 2k +5) -4 ( -5 +1) -k (-1-2k) = 48
=> 2k +5 +16 +k +2k =48
=> 5k = 48 - 21
=> k = 27/5
=> k = 5.4 units
=> [ 1 ( 2k +5) -4 ( -5 +1) -k (-1-2k) = 48
=> 2k +5 +16 +k +2k =48
=> 5k = 48 - 21
=> k = 27/5
=> k = 5.4 units
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