Find k, if the area of triangle is 24 square units : (1,-1), (-4,2k) and (-k,-5)
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Answered by
2
24 = 1 -4 -k 1
-1. 2k -5 -1
24 = (2k +20 +k) -(4-2k²-5)
24 = 3k +20 -(-2k²-1)
24 = 3k +20 +2k² +1
24 = 2k²+3k+21
24-21 = 2k² + 3k
3 = 2k² + 3k
2k² + 3k = 3
2k²+3k-3=0
solve the equation
-1. 2k -5 -1
24 = (2k +20 +k) -(4-2k²-5)
24 = 3k +20 -(-2k²-1)
24 = 3k +20 +2k² +1
24 = 2k²+3k+21
24-21 = 2k² + 3k
3 = 2k² + 3k
2k² + 3k = 3
2k²+3k-3=0
solve the equation
Answered by
2
i dont know wheather its correct but try....
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Prithvi23102003:
Tq so much frnd
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