Question

find k if the equation 2x +3y- 2=0, 2x+4y-k =0, x-2y+3k=0 are constant​

Answer 1

Step 1: By equating the first two equations we get a product of (y+2=k)

Step 2: By equating second and third equation we get a product of (8y-7k=0)

Step 3: By equating the both the products we can obtain :-

$\implies \: 15k = 16$

$\implies \: k = \frac{16}{15}$

$\implies \: k = 1.066$