Question

find k if the equation is consistent
(k+1)x+(k-1)y+(k-1)=0
(k-1)x+(k+1)y+(k-1)=0
(k-1)x+(k-1)y+(k+1)=0

The one who solves the whole answer will be marked as brainliest.​

Answer 1

Answer:

K = -1

Step-by-step explanation:

Subtracting all equations together, x and y terms get canceled.

Remaining terms are:

(k-1)-(k-1)-(k+1)=0

= k-1-k+1-k-1 = 0

-k-1=0

Hence k=-1

Hope it helps:)