Question

Find K, if the equations below are consistent
2x + 3y - 2 = 0,
2x + 4y - K = 0,
x-2y + 3k=0​

Answer 1

Answer:

Step-by-step explanation:

2x+3y−7=0→(1)

(K−1)x+(K+2)−3K=0

For, these two equations to have infinite solutions,

K−12=K+23=−3K−7

⇒K−12=K+23

⇒3K−3=2K+4

⇒K=7

Now, K−12=−3K−7

⇒7K−7=6K

⇒K=7

∴ For K=7, these equations will have infinite solutions.

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