Find k, if the line 4x - y = 1 is perpendicular to the line 5x - ky = 2?
Options:
1) 20
2) -20
3) 4
4) -4
Answers
Answered by
12
Hi ,
4x - y = 1 -----( 1 )
Slope of above line = m1
m1 = - ( x - coefficient ) /( y-coefficient)
m1 = - 4/( - 1 ) = 4
5x - ky = 2 ------( 2 )
Slope of the line = m2 = - 5/( - k )
m2 = 5/k
According to the problem given ,
Two lines are perpendicular each
other ,
Therefore ,
m1 × m2 = -1
4 × ( 5/k ) = -1
20/k = -1
k = -20
I hope this helps you.
:)
4x - y = 1 -----( 1 )
Slope of above line = m1
m1 = - ( x - coefficient ) /( y-coefficient)
m1 = - 4/( - 1 ) = 4
5x - ky = 2 ------( 2 )
Slope of the line = m2 = - 5/( - k )
m2 = 5/k
According to the problem given ,
Two lines are perpendicular each
other ,
Therefore ,
m1 × m2 = -1
4 × ( 5/k ) = -1
20/k = -1
k = -20
I hope this helps you.
:)
veeru112:
thanks for the explanation
Answered by
5
slope of line 4x-y=1
=>y=4x-1
slope=(4/1)
slope of line 5x-ky=2
=>y=(2-5x)/k
=>y=(-5/k)x+2/k
slope is -(5/k)
But, we know that the product of median of 2 perpendicular line=-1
so,
-5/k×4/1=-1
-20/k=-1
k=20
=>y=4x-1
slope=(4/1)
slope of line 5x-ky=2
=>y=(2-5x)/k
=>y=(-5/k)x+2/k
slope is -(5/k)
But, we know that the product of median of 2 perpendicular line=-1
so,
-5/k×4/1=-1
-20/k=-1
k=20
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