find k if the line passing through points p ( -12,-3 ) and Q( 4 , k ) has slope 1/2
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Answered by
2
answer=5
Explanation:
slope=(y2-y1)/(x2-x1)
1/2=[k-(-3)]/[4-(-12)]
1/2=(k-3)/16
0.5×16=k+3
8.0=k+3
k=8-3
k=5
Answered by
4
Answer:
fully explained
hope it will help you:-))
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