find K if the line passing through points P (- 12 - 3) and Q (4,k) has slope 1/2
Answers
Answered by
55
Heya mate...
Slope =y2-y1/x2-x1
1/2=k+3/4+12
1/2=k+3/16
1=k+3/8
K+3=8
K=5
@skb
Slope =y2-y1/x2-x1
1/2=k+3/4+12
1/2=k+3/16
1=k+3/8
K+3=8
K=5
@skb
Answered by
11
Hello Dear..
Here's your answer
-------------------
slope is (y2-y1)/(x2-x1) = (k+3)/ 16
given that (k+3)/16 = 1/2
so, k = 5
---------------------
Hope it helps you
Mark as brainliest if u lyk it
Here's your answer
-------------------
slope is (y2-y1)/(x2-x1) = (k+3)/ 16
given that (k+3)/16 = 1/2
so, k = 5
---------------------
Hope it helps you
Mark as brainliest if u lyk it
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