Question

Find k if the quadratic equation has equal roots : kx (x-2) +6 = 0

Answer 1

k = 6

Given,

$kx(x - 2) + 6 = 0 \\ = > k {x}^{2} - 2kx + 6 = 0$

Since the roots are equal,

$= > {b}^{2} = 4ac \\ = > ( - 2k) {}^{2} = 4(k)(6) \\ = > 4 {k}^{2} = 4k(6) \\ = > 4 {k}^{2} = 24k \\ = > k = 6$

k = 6

HOPE THIS HELPS!