Question

find k, if the root's of the
quadratic equation kx^2-4x+4=0 are equal​

Answer 1

Answer:

The value of $\\ k$ is 1.

Step-by-step explanation:

Quadratic Equation is : $\\ kx^{2} -4x + 4$

We know,

That roots of the equation are equal.

∴ The Discriminant of the equation is 0.

Discriminant = [ $\\ b^{2} -4ac$ ]

In this equation,

$\\ a = k, b = (-4), c = 4$

∴ $\\ (-4)^{2} - 4[(k)(4)] = 0$

⇒ $\\ 16 -16k = 0$

⇒ $\\ 16k = 16$

⇒ $\\ k = \frac{16}{16}$

∴ $\\ k = 1$

-----------------------------------------------------------------------------------------------------------------

Please mark as Brainliest!!!