find k if the roots of the equation kx(x-2)+6=0 are equal?
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HEYA!
The answer is in the attachment provided. Please refer to it once.
Hope this helps mate!
The answer is in the attachment provided. Please refer to it once.
Hope this helps mate!
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Answered by
1
applying b^2-4ac=0
4k^2-4×6×k =0
4k^2=24k
k^2=6k
k(k-6)=0
k=6
as k can't be 0
4k^2-4×6×k =0
4k^2=24k
k^2=6k
k(k-6)=0
k=6
as k can't be 0
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