Question

Find k, if the sum of the zeroes of polynomial x²-(k+6)x+2(2k-1) is half their product?​

Answer 1

Answer:

k=7

Explanation:

For given polynomial x²-(k+6)x+2(2k-1)

Here

a=1 , b= -(k=6), c=2(2k-1)

Give that,

ஃ Sum of zeroes = ½ ( product of zeroes )

=> -[-(k+6)] = ½ ×2(2k-1)

______ _____

1 1

=> k+6 =2k-1

=> 6+1=2k-k

=> k=7

Therefore, the value of k=7