Question

find k if the sum of the zeroes of the zeroes of the polynomial x^2 -(k+6) x+2 (2k-1) is half their product ​

Answer 1

Heya!!

let it's two zero's be a and b

FOR A GENERAL QUADRATIC POLYNOMIAL SAY F(x) = ax² + bx + c

WE HAVE

a + b = -b/a And a × b = c/a

=>

x² - ( k + 6 )x + 2 ( 2k - 1 )

a + b = ( k + 6 )

And

( a × b ) = 2 ( 2k - 1 )

ACCORDING TO THE GIVEN QUESTION!

( a + b ) = ( a × b )/2

( k + 6 ) = 2×( 2k - 1 )/2

( k + 6 ) = 2k - 1

-k = -7

k = 7

Answer 2

$\huge \red{here \: is \: your \: solution \: bye \: forever}$