Question

find k if x + 1 is a factor of 2x ^2+kx +1 do it fast please ​

Answer 1

Answer:The value of k=2

p(x)=2x square+kx

Factor of p(x) is (x+1)

therefore, zero of p(x)=(-1)

p(-1)=2(-1)square+ k(-1)=0

2-k=0

-k=-2

k=2

Answer 2

Answer:

k = 3

Step-by-step explanation:

Let,

p(x) = 2x^2 + kx + 1

Given ,

x+ 1 is a factor of p(x)

Then By Factor Theorem,

[x + 1 = 0 => x = -1]

(Putting value of x in p(x))

p(-1) = 0

Solution,

=> p(-1) = 0

=> 2(-1)^2 + k(-1) + 1 = 0

=> 2 - k + 1 = 0

=> 3 - k = 0

=> 3 = k

Hence,

Value of k = 3 when (x+1) is a factor of (2x^2 + kx + 1) (Ans)

Thank you very much for the thanks